Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: Rs.

There are no items in this cart.
Continue Shopping
Shreyans Sharma Grade: 11

vikas sir the question i posted was an iit 2009 question n the number of stereoisomers has been given as 6..... n cud u please tel me how do we get 2 enantiomers in the cis form as it is optically inactive.... please explain to me briefly how did u calculate the enantiomers in both. i am too confused wid it.... can u please refer me a way to slove such problems

7 years ago

Answers : (1)

vikas askiitian expert
510 Points

dear shreyans here is the detailed solution ,  (d means dextro & L means leavo)

     left assymetric carbon          double bond         right assymetric carbon

1)           d                                cis                                 d

2)           d                                trans                            d

3)           L                                cis                                 L

4)           L                                trans                             L

5)           d                               cis                                  L

6)           L                                trans                             L

from this table , all d-L pairs are enantiomers & those paires which are not enantiomers are diasteriomers ....

1 - 3  & 2-4 are enantiomers , total enatiomers for cis are 2 , for trans 2 ...

total steriomers are 6 ....

7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!! Click Here for details