vikas sir the question i posted was an iit 2009 question n the number of stereoisomers has been given as 6..... n cud u please tel me how do we get 2 enantiomers in the cis form as it is optically inactive.... please explain to me briefly how did u calculate the enantiomers in both. i am too confused wid it.... can u please refer me a way to slove such problems

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vikas askiitian expert · Answer

dear shreyans here is the detailed solution , (d means dextro & L means leavo)

left assymetric carbon double bond right assymetric carbon

1) d cis d

2) d trans d

3) L cis L

4) L trans L

5) d cis L

6) L trans L

from this table , all d-L pairs are enantiomers & those paires which are not enantiomers are diasteriomers ....

1 - 3 & 2-4 are enantiomers , total enatiomers for cis are 2 , for trans 2 ...

total steriomers are 6 ....

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