vikas sir the question i posted was an iit 2009 question n the number of stereoisomers has been given as 6..... n cud u please tel me how do we get 2 enantiomers in the cis form as it is optically inactive.... please explain to me briefly how did u calculate the enantiomers in both. i am too confused wid it.... can u please refer me a way to slove such problems
vikas sir the question i posted was an iit 2009 question n the number of stereoisomers has been given as 6..... n cud u please tel me how do we get 2 enantiomers in the cis form as it is optically inactive.... please explain to me briefly how did u calculate the enantiomers in both. i am too confused wid it.... can u please refer me a way to slove such problems