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Please tell me in detail how to find no of geometrical isomer and no of optical isomers of a given compound and sir does R-Z AND E-S configuration in syllabus
Hi For a molecule with multiple chiral centers, the number of possible diastereomers is given by the equation: x = 2n where x is the number of possible isomers and n is the number of stereogenic centers. Thus, for molecules with two stereogenic centers there are four possible stereoisomers. For cholesterol, with eight stereogenic centers, there are 256 possible stereoisomers, etc. To know a detailed method then please follow the link: resources.metapress.com/pdf-preview.axd or www.springerlink.com/content/m373j2117257r371/ . RZ and ES are included in the syllabus.
Hi
For a molecule with multiple chiral centers, the number of possible diastereomers is given by the equation:
x = 2n where x is the number of possible isomers and n is the number of stereogenic centers. Thus, for molecules with two stereogenic centers there are four possible stereoisomers. For cholesterol, with eight stereogenic centers, there are 256 possible stereoisomers, etc.
To know a detailed method then please follow the link: resources.metapress.com/pdf-preview.axd or www.springerlink.com/content/m373j2117257r371/ .
RZ and ES are included in the syllabus.
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