2.26 gm of a sample of dolomite containing only caco3 and mgco3 were dissolved in 700 ml of 0.1 N. The solution was diluted to 2.5 l. 25ml of this solution required 20 ml of 0.01 naoh solution for complete neutralisation. Find %composition of the ore.

Question

Arun · Answer

equivalent of caco3+equivalent of mgco3 = 36 moles+moles=36/2000 moles+moles=0.018 w/100+1.64-w/84 = 0.018 164-16w = 151.2 16w=12.8 w=0.8 gm weight of caco3 = 0.8 gm weight of mgco3 = 0.84 gm percentage composition of caco3 = 0.8/1.64*100 = 48.79 percentage composition of mgco3 = 51.21

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2.26 gm of a sample of dolomite containing only caco3 and mgco3 were dissolved in 700 ml of 0.1 N. The solution was diluted to 2.5 l. 25ml of this solution required 20 ml of 0.01 naoh solution for complete neutralisation. Find %composition of the ore.

2.26 gm of a sample of dolomite containing only caco3 and mgco3 were dissolved in 700 ml of 0.1 N. The solution was diluted to 2.5 l. 25ml of this solution required 20 ml of 0.01 naoh solution for complete neutralisation. Find %composition of the ore.

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2.26 gm of a sample of dolomite containing only caco3 and mgco3 were dissolved in 700 ml of 0.1 N. The solution was diluted to 2.5 l. 25ml of this solution required 20 ml of 0.01 naoh solution for complete neutralisation. Find %composition of the ore.

2.26 gm of a sample of dolomite containing only caco3 and mgco3 were dissolved in 700 ml of 0.1 N. The solution was diluted to 2.5 l. 25ml of this solution required 20 ml of 0.01 naoh solution for complete neutralisation. Find %composition of the ore.

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