#1problems:a titration is performed by adding 0.600M KOH to 40.0 ML of 0.800 M HCL.. calculate the ph before addition of any koh.. calculate the ph after addition of 5.0 ML of the base..
avo , 10 Years ago
Grade 12th pass
1 Answers
Sunil Kumar FP
Last Activity: 10 Years ago
equation
koh+hcl----kcl + h2o
millimole of hcl=40*.8=32
millimole of koh=.6*5=3
ph before addition of koh=-log(h+)=-log.8=.097
after addition of koh=hcl remains=32-3=29miilimole
volume of the solution=45ml
concentration of hcl=29/45=.644
log(.644)=.191
thanks and regards
sunil kr
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