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.1.4 grams of hydrocarbon on combustion gives 1.8 grams of water fin emperical formulae of compound. options are 1 . CH 2 . CH2 3 . CH3 4 . CH4

.1.4 grams of hydrocarbon on combustion gives 1.8 grams of water fin emperical formulae of compound. options are 
1 . CH
2 . CH2
3 . CH3
4 . CH4
 
 
 
 
 
 
 
 
 
 
 
 

Grade:12th pass

1 Answers

Rishav Dugar
13 Points
6 years ago
Let molecular formula be CxHy1.8 g of water equals to 0.1 mole of water equals to 0.2 moles of H atomNow H is coming from hydrocarbon so `no. of moles of hydrocarbon × y=0.2`=》(1.4/(12 × X + 1 × y )) × y = 0.2On solving y/x = 2Hence empirical formula is CH2

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