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1.0 g of a sample containing NaOH, Na2 CO3 and inert impurities was dissolved in water to form 100 mL of stock solution. A 10 mL portion of the stock solution was reacted with 15 mL of 0.140 mol / L HCl solution in the presence of phenolphthalein. In a separate titration, 10 mL of the stock solution was reacted with 20 mL of the same acid solution to achieve equivalence point using methyl orange as indicator. Based on this information, determine the percentages by mass of NaOH and Na2CO3 in the original sample.Data:Reactions in the presence of phenolphthaleinNaOH + HCl → NaCl + H 2 ONa2CO3 + HCl → NaHCO3 + NaClReactions in the presence of methyl orangeNaOH + HCl → NaCl + H 2 ONa 2 CO 3 + 2HCl → NaCl + H 2 O + CO 2 Answer: 40% NaOH and 53% Na 2 CO 3

1.0 g of a sample containing NaOH, Na2 CO3 and inert impurities was dissolved in water to form 100 mL of stock solution. A 10 mL portion of the stock solution was reacted with 15 mL of 0.140 mol / L HCl solution in the presence of phenolphthalein. In a separate titration, 10 mL of the stock solution was reacted with 20 mL of the same acid solution to achieve equivalence point using methyl orange as indicator. Based on this information, determine the percentages by mass of NaOH and Na2CO3 in the original sample.Data:Reactions in the presence of phenolphthaleinNaOH + HCl → NaCl + H 2 ONa2CO3 + HCl → NaHCO3 + NaClReactions in the presence of methyl orangeNaOH + HCl → NaCl + H 2 ONa 2 CO 3 + 2HCl → NaCl + H 2 O + CO 2Answer: 40% NaOH and 53% Na 2 CO 3

Grade:6

1 Answers

Mohammed Kasib Siddiqui
119 Points
5 years ago
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