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Grade: 11
        
Please explain the image problem fully not only answer I need to be  explained......... Please........,.,..,.,.
5 months ago

Answers : (1)

Arun
22005 Points
							

Height of the cliff, h = 240 m

 

Velocity of Stone 1, y₁= 10 m/s

 

Velocity of Stone 2, y₂ = 40 m/s

 

To calculate the time when stone 1 strikes the ground, use Equation of Motion,

 

            h = ut + ½ gt²

 

            -240 = 10 × t – ½ × 10 × t²

 

            5t² -10t -240 = 0

 

            t² – 2t – 48 = 0

 

            t = 8 sec and -6 sec

 

To calculate the time when stone 2 strikes the ground, use Equation of Motion,

 

            h = ut + ½ gt²

 

            -240 = 40 × t – ½ × 10 × t²

 

            5t² -40t -240 = 0

 

            t = 12 sec

 

The relative velocity of the two stone = y₂ – y₁ = 40 – 10 = 30 m/s

 

Therefore, graph of y₂ – y₁ against time is a straight line.

 

Hence, when the stone strikes the ground, the relative velocity will increase up to 12 seconds as shown in graph (3).


 
5 months ago
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