MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        
  • Calculate the % dissociation of H2S(g) ,if 0.1 mole of H2S is kept in 0.4 litre vessel at 1000K.For the reaction 2H2S = 2H2+S2 , the value of kis 1×10−6
8 months ago

Answers : (1)

Nilabh
35 Points
							
(0.1-x )    (  x )    (x/2)
2H2S  >
 
At equilibrium:-  (0.1-x)/V
Therefore ::::   Kc= {( x/V)^2(x/2V)} / (0.1-x/v)^2
    =>  1.0×10^-6 =( x^3) / 2V(0.1)^2
    =>   x^3 = 2×0.4×0.1×10^-6
    =>   x = 2×10 ^-3
   So % dissociation = (2×10^-3×100) / 0.1
                                   = 2%
8 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details