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Are you asking a ncert textbook question .Ok, velocity of the plane (v)=500kmph=139 mps.Angle at which it made the turn(x) = 30°Let' s take acceleration due to gravity(g) to be 9.8mps^-2.Then ,
Using the formula,v^2/rg = tanx.where r= radius of the loop.Putting the values we get19321/9.8r=0.57
r= 19321/9.8×0.57r=3458.8 metres.
Or ,the radius of the loop executed by the plane is 3.45 km.
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