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Grade: 12th pass
        
A simple harmonic oscillator has an amplitude A and time period T the time required by it to travel from x=A to x=A/2 is?
one year ago

Answers : (2)

Eshan
askIITians Faculty
2095 Points
							Dear student,

Since the particle starts from x=A, the equation of motion can be written as

x=Acos\omega t
Hence forx=A/2,
A/2=Acos\omega t\implies \omega t=\dfrac{\pi}{3}
\implies t=\dfrac{\pi}{3\omega}
SinceT=\dfrac{2\pi}{\omega},
t=T/6
one year ago
Dev Kumar
33 Points
							
You could've been answered the question with the help of concept of phaser diagram.
In this, draw a circle of radius A on a Cartesian sheet, and on y-axis mark a point A/2 on +y-axis,and at the end point of circle mark point A 
Particle shm => A----->A/2 ; can be considered as A/2---->A
Draw a line  from A/2 projecting on the circle, join the origin and projection, take angle along y-axis and mark it as μ.
Now cos μ= A/2A= 1/2 => μ=π/3 
We know that,
                           μ/t= 2π/T
=> π/3t=2π/T
=> t= T/6
8 months ago
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