Flag Most Scoring Topics in IIT JEE> A hemispherical portion of radius R is re...
question mark

A hemispherical portion of radius R is removed from the bottom of a cylinder of radius R. The volume of the remaining cylinder is V and its mass is M. It is suspended by a string in a liquid of density r where it stays vertical. The upper surface of the cylinder is at a depth h below the liquid surface. the force on the bottom of the cylinder by the liquid is

sandeep matla , 7 Years ago
Grade 11
anser 1 Answers
Arun

Last Activity: 7 Years ago

Dear Sandeep

Using Archimedes principle,

Fbottom - hρg(πR2) = Vrg

So, Fbottom = ρg(V + πR2h)

(ignoring atmospheric pressure)

Regards

Arun (askIITians forum expert)

 A Piston, Which has A Hemispherical Portion of Radius R is Removed from the Bottom of a Cylinder of Radius R.

star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments