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A hemispherical portion of radius R is removed from the bottom of a cylinder of radius R. The volume of the remaining cylinder is V and its mass is M. It is suspended by a string in a liquid of density r where it stays vertical. The upper surface of the cylinder is at a depth h below the liquid surface. the force on the bottom of the cylinder by the liquid is

A hemispherical portion of radius R is removed from the bottom of a cylinder of radius R. The volume of the remaining cylinder is V and its mass is M. It is suspended by a string in a liquid of density r where it stays vertical. The upper surface of the cylinder is at a depth h below the liquid surface. the force on the bottom of the cylinder by the liquid is
 

Grade:11

1 Answers

Arun
25758 Points
4 years ago
Dear Sandeep

Using Archimedes principle,

Fbottom - hρg(πR2) = Vrg

So, Fbottom = ρg(V + πR2h)

(ignoring atmospheric pressure)

Regards

Arun (askIITians forum expert)

 A Piston, Which has A Hemispherical Portion of Radius R is Removed from the Bottom of a Cylinder of Radius R.

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