if the constant term of the binomial expansion is (2x -1/x)^n is -160 then what is the value of n?

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Sher Mohammad · Answer

kth term of the expansion is nCk 2 k *x k* (-1) n-k *x k-n constant term so k=n-k =>k=n/2 now nCn/2 2 n/2 =160 and n/2 must be odd for n=6 the equation holds. Sher Mohammad faculty askiitians

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if the constant term of the binomial expansion is (2x -1/x)^n is -160 then what is the value of n?

if the constant term of the binomial expansion is (2x -1/x)^n is -160 then what is the value of n?

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if the constant term of the binomial expansion is (2x -1/x)^n is -160 then what is the value of n?

if the constant term of the binomial expansion is (2x -1/x)^n is -160 then what is the value of n?

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