A body is projected up with a velocity equal to 3/4 of the escape velocity from the surface of the Earth. The height it reaches is (Radius of Earth is R)

Dear Siva,

vi=(3/4) of escape velocity from the surface of the earth = (3/4)*11200 = 8400 m/s
vf=0 m/s
t=time
g=9.8 m/s2
d=distance

vf=vi-gt
0=vi-gt
t=vi/g

now, d=(vf-vi)t/2
d=(vi)^2/2g

so,
d= 3600000 m = 3600km

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Dear Siva,

Dont post ame query again and again.

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