Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
points A and B are in the first quadrant. point Ois the origin.If the slope of OA is 1, slope of OB is 7 and OA= OB, then slope of AB is -------
Hi Deepu,
Draw the figure.
Let A be angle of OA with x-axis, and B be the angle of OB with x-axis.
Let m be the required slope. Let Q be the (in acute sense) angle made by AB with horizontal.
So m = -tanQ
Now tanA=1, or SinA=1/root2 and cosA=1/root2
and tanB=7, or SinB=7/root50 and cosB=1/root50.
From figure, tanQ = (sinB-sinA)/(cosA-cosB)
or tanQ = (7root2 - root50)/(root50 - root2) = (7-5)/(5-1) = 1/2
or required slope m = -1/2.
Regards,
Ashwin (IIT Madras).
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !