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because to pursue with active mode or during the time of amplication of a signal BE & CB junctions need to be biased as forward & reverse respectively in case of npn CE transistor..
by increasing Vi, Ib goes higher.. Ic goes much higher i.e. β times Ib where β is amplification factor, having a large value.. results drop across Rc, Ic.Rc
by applying KVL we get an eqⁿ Vi = Vo - Ic.Rc or, Vo = Vi - Ic.Rc
to obtain AC characteristics by applying an AC biasing makes drop across Rc greater value than i/p voltage Vi because of β.Ib
∵ Ic.Rc > Vi ∴ Vo must be -ve.. or, Vo = -Vi
i.e. Vcb > Vbb results reverse biasing goes superior than forward biasing..
so why, a 180⁰ phase shift takes place..
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