Adarsh
Last Activity: 7 Years ago
Dear Preeti ,
Let the threshold wavelength be λ0 ,
Now A/Q 3V0 = hc/(λ0 – λ) …..... ( 1 )
V0= hc/(λ0 – 2λ) …....... ( 2 )
dividing 1 by 2 we get , 3 = (λ0 – 2λ) / (λ0 – λ) => λ0 = λ/2 .
Hence the threshold wavelength is half of lambda..
Thanks and Regards
Adarsh