Navjyot Kalra
Last Activity: 10 Years ago
Hello Student,
Please find the answer to your question
No. of photons /sec
= Energy incident on platinum surface per second / Energy of on photon
No. of photon incident per second
= 2 x 10 x 10-4 / 10. 6 x 1.6 x 10-19 = 1. 18 x 1014
As 0.53% of incident photon can eject photoelectrons
∴ No. of photoelectrons ejected per second
= 1.18 x 1014 x 0.53 / 100 = 6.25 x 1011
Minimum energy = 0 eV,
Maximum energy = (10.6 – 5.6 ) eV = 5eV
Thanks
Navjot Kalra
askIITians Faculty