Modern Physics> When 0.15kg of ice at 0(degree)C mixed wi...

When 0.15kg of ice at 0(degree)C mixed with 0.3kg of water at 50(degree)C in a container. what is the resulting temperature? S (means) see S ice=2100j/kg (degree)C; S water=4190j/kg(degree)C;AND L f=3.34into10^5j/kg

theja , 12 Years ago

Grade 9

1 Answers

Arun Kumar

See all of the ice will be melted because

$0.3*50*4190$

can melt 0.18kg of ice

but since we have to take care of temperature rise too.

$0.3*4190(50-T)=0.15*3.39*10^5+0.45*T*4190 \\=>T=3.81C$

Arun Kumar

IIT Delhi

Askiitians Faculty

Last Activity: 11 Years ago

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Modern Physics> When 0.15kg of ice at 0(degree)C mixed wi...

When 0.15kg of ice at 0(degree)C mixed with 0.3kg of water at 50(degree)C in a container. what is the resulting temperature? S (means) see S ice=2100j/kg (degree)C; S water=4190j/kg(degree)C;AND L f=3.34into10^5j/kg

theja , 12 Years ago

Arun Kumar

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