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Grade: 12

                        

water is flowing in a river at 2.5 m÷s.the river is 40m wide with an average depth of 6.0m.compute the power available from the water current.

6 years ago

Answers : (3)

Arpit Kumar
31 Points
							Take the time of flow to be 1 second.
Volume of water=2.5*40*6=600m^3
Density of water is 1000 kg/m^3
Mass of water=600000 kg
Kinetic Energy of water=1/2*600000*2.5*2.5=1875000 J
Power generated=1875000 W
						
6 years ago
lokesh palingi
44 Points
							THANK U SIR,
						
6 years ago
chaitnyakishore
26 Points
							Power(P)=work/time
                =(potential energy+kinetic energy)/timet
                =[mgh+(mv²/2)]/t
                =[m/t]*[gh+(v²/2)]
 Therefore P =[density(d)*volume(V)/t]*[gh+(v²/2)]
                But Volume/time=area(A)*velocity(v)
 Therefore P=[dAv]*[gh+(v²/2)]
                      =[1000*40*6*2.5]*[g(0)+{(2.5)²/2}]
                      =1000*240*2.5*3.125
                      =1875000W
                      =1.875MegaWatts.
						
6 years ago
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