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```
water is flowing in a river at 2.5 m÷s.the river is 40m wide with an average depth of 6.0m.compute the power available from the water current.

```
6 years ago

```							Take the time of flow to be 1 second.
Volume of water=2.5*40*6=600m^3
Density of water is 1000 kg/m^3
Mass of water=600000 kg
Kinetic Energy of water=1/2*600000*2.5*2.5=1875000 J
Power generated=1875000 W
```
6 years ago
```							THANK U SIR,
```
6 years ago
```							Power(P)=work/time
=(potential energy+kinetic energy)/timet
=[mgh+(mv²/2)]/t
=[m/t]*[gh+(v²/2)]
Therefore P =[density(d)*volume(V)/t]*[gh+(v²/2)]
But Volume/time=area(A)*velocity(v)
Therefore P=[dAv]*[gh+(v²/2)]
=[1000*40*6*2.5]*[g(0)+{(2.5)²/2}]
=1000*240*2.5*3.125
=1875000W
=1.875MegaWatts.
```
6 years ago
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