Grade upto college level Modern Physics

Visible light has wavelengths in the range of 400 nm to 780 nm. Calculate the range of energy of the photons of visible light.

Shane Macguire

12 Years agoGrade upto college level

1 Answer

Navjyot Kalra

12 Years ago

Sol. λ base 1 = 400 nm to λ base 2 = 780 nm E = hv = hc/λ h = 6.63 * 10^-34 j – s, c = 3 * 10^8 m/s, λ base 1 = 400 nm, λ base 2 = 780 nm E base 1 = 6.63 * 10^-34 * 3 * 10^8/400 * 10^-9 = 6.63 *3/4 * 10^-19 = 5 * 10^-19 J. E base 2 = 6.63 *3/47.8 * 10^-19 = 2.55 * 10^-19 J So, the range is 5 * 10^-19 J to 2.25 * 10^-19 J.

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Visible light has wavelengths in the range of 400 nm to 780 nm. Calculate the range of energy of the photons of visible light.

Shane Macguire

1 Answer

Navjyot Kalra

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