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Grade: 11
        
Ultraviolet light of wavelengths 800 Å when allowed to fall on hydrogen atoms in their ground state is found to liberate electrons with kinetic energy 1.8 eV  and 4.0 eV respectively. Find the value of Planck’s constant.
5 years ago

Answers : (1)

Kevin Nash
askIITians Faculty
332 Points
							
hc / λ1 – hc / λ0 = K.E. 1 ….(i)
And hc / λ2 – hc / λ0 = K.E.2 ….(ii)
⇒ hc / λ1 - hc / λ2 = K.E.1 – K.E2
⇒ hc [λ2 - λ1 / λ1 λ2] =K.E.1 – K.E2
∴ h = (K.E. – K.E.­21 λ2 / c (λ2 – λ1)
= (1.8 – 4) x 1. 6 x 10-19 x 800 x 10-10 x 700 x 10-10 / 3 x 108 x (700 - 800) x 10-10
= 6.6 x 1034 J.s.
5 years ago
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