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Grade: 12 

                        
Ultraviolet light of wavelength Lambda 1 and Lambda 2 when allowed to fall on a hydrogen atoms in their Ground state is found to liberate electrons with kinetic energy 1.8ev and 4ev respectively.find the value of lambda 1/lambda 2 (L1/L2)
3 years ago

Answers : (1)

Amarjit
105 Points 
							Since electrons are liberated hence the total energoes must be 15.4eV and 17.6eV respectively.Now using the formula E=hc/lambda we will get lambda in both the cases keeping hc= 12400( lamba in the order of angstrom order).Now just take their ratio.
3 years ago
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