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Two particles are performing simple harmonic motion in a straight line about the same equilibrium point. The amplitude and time period for both particles are same and equal to A and T, respectively. At time t=0 one particle has displacement A while the other one has displacement 2 A − and they are moving towards each other. If they cross each other at time t, then t is :

Two particles are performing simple
harmonic motion in a straight line about
the same equilibrium point. The amplitude
and time period for both particles are same
and equal to A and T, respectively. At time
t=0 one particle has displacement A while
the other one has displacement 2
A −
and
they are moving towards each other. If they
cross each other at time t, then t is :

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1 Answers

sharib khan
36 Points
6 years ago
After T/4 time both the particle will be at same position . they meet at the mean position.
this is because both the particle have same amplitude and time period and at t=0 they are at opposite extremes so it takes T/4 time to reach the mean position
 

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