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Two particles are performing simpleharmonic motion in a straight line aboutthe same equilibrium point. The amplitudeand time period for both particles are sameand equal to A and T, respectively. At timet=0 one particle has displacement A whilethe other one has displacement 2A −andthey are moving towards each other. If theycross each other at time t, then t is :

VISHAL GUPTA , 8 Years ago
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sharib khan

Last Activity: 8 Years ago

After T/4 time both the particle will be at same position . they meet at the mean position.
this is because both the particle have same amplitude and time period and at t=0 they are at opposite extremes so it takes T/4 time to reach the mean position
 

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