Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Two particles are performing simple harmonic motion in a straight line about the same equilibrium point. The amplitude and time period for both particles are same and equal to A and T, respectively. At time t=0 one particle has displacement A while the other one has displacement 2 A − and they are moving towards each other. If they cross each other at time t, then t is :

Two particles are performing simple
harmonic motion in a straight line about
the same equilibrium point. The amplitude
and time period for both particles are same
and equal to A and T, respectively. At time
t=0 one particle has displacement A while
the other one has displacement 2
A −
and
they are moving towards each other. If they
cross each other at time t, then t is :

Grade:

1 Answers

sharib khan
36 Points
5 years ago
After T/4 time both the particle will be at same position . they meet at the mean position.
this is because both the particle have same amplitude and time period and at t=0 they are at opposite extremes so it takes T/4 time to reach the mean position
 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free