Modern Physics> Two cu 64 nuclei touch each other. The el...

Two cu⁶⁴ nuclei touch each other. The electrostatics repulsive energy of the system will be

Smita Nanasaheb khandbahale , 6 Years ago

Grade 12

1 Answers

Arun

Dear student

Radius of each nuclei = R (A)^1/3 = 1.2 * (64)^1/3 = 1.2 * 4 = 4.8

distance between two nuclei = 2 * 4.8 = 9.6

Hence potential energy = k q^2 / r = 126.15 Mev

Last Activity: 6 Years ago

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Modern Physics> Two cu 64 nuclei touch each other. The el...

Two cu64 nuclei touch each other. The electrostatics repulsive energy of the system will be

Smita Nanasaheb khandbahale , 6 Years ago

Arun

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