Three particles each of mass M are place at the vertices of an equilateral triangle of side a the gravitational filed intensity at the centroid of the triangle is

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Adarsh · Answer

The gravitational field intensity will be zero , because centroid is equidistant from its vertices .. and gravitational field due to each mass will be equal but if we break it itno its component the resultant will be zero .. Hope this will help you …

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Three particles each of mass M are place at the vertices of an equilateral triangle of side a the gravitational filed intensity at the centroid of the triangle is

Three particles each of mass M are place at the vertices of an equilateral triangle of side a the gravitational filed intensity at the centroid of the triangle is

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Three particles each of mass M are place at the vertices of an equilateral triangle of side a the gravitational filed intensity at the centroid of the triangle is

Three particles each of mass M are place at the vertices of an equilateral triangle of side a the gravitational filed intensity at the centroid of the triangle is

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