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Grade: 11
        
This question belongs to the topic- photoelectric effect of class 11 modern physics.
one year ago

Answers : (1)

Arun
24740 Points
							
The electric field becomes 0 1.2 * 10^45 times per second. ∴ Frequency = 1.2 * 10^15/2 = 0.6 * 10^15 hv = ∅ base 0 + KE ⇒ hv - ∅ base 0 = KE ⇒ KE = 6.63 * 106-34 *0.6 * 10^15/1.6 * 10^-19 – 2 = 0.482 ev = 0.48 ev.
one year ago
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