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This question belongs to the topic- photoelectric effect of class 11 modern physics.

This question belongs to the topic- photoelectric effect of class 11 modern physics.

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Grade:11

1 Answers

Arun
25750 Points
4 years ago
The electric field becomes 0 1.2 * 10^45 times per second. ∴ Frequency = 1.2 * 10^15/2 = 0.6 * 10^15 hv = ∅ base 0 + KE ⇒ hv - ∅ base 0 = KE ⇒ KE = 6.63 * 106-34 *0.6 * 10^15/1.6 * 10^-19 – 2 = 0.482 ev = 0.48 ev.

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