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Grade 12th passModern Physics

the wavelength of an electron of energy 10KeV will be ?

Profile image of Sher Singh
9 Years agoGrade 12th pass
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1 Answer

Profile image of Parvin
9 Years ago
Electrons follow de broglies eq.Lambda =h/mv Kinetic energy =1/2 mv^2KE=1/2×mv^2m(KE)=mv^2÷2×massM (KE)=m^2×v^2÷2=(p)^2÷2P=root (2M (ke))So lambda=h÷(root2m (KE))Putting the values6.63×10^-34÷root (18.2×10^-27)On solving...we get Wavelength =0.49×10^-47

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