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Grade: upto college level
        The short-wavelength limit shifts by 26 pm when the operating voltage in an X-ray tube is increased to 1.5 times the original value. What was the original value of the operating voltage?
5 years ago

Answers : (1)

Navjyot Kalra
askIITians Faculty
654 Points
							Given λ’ = λ – 26 pm, V’ = 1.2 V
Now, λ = hc/ev , λ’ = hc/ev’
Or λV = λ’V’
⇒ λV = (λ – 26 * 10^-12)* 1.5 V
⇒ λ = 1.5 λ – 1.5 * 26 * 10^–12
⇒ λ = 39* 10^-12/0.5 = 78 * 10^12 m
V = hc/eλ = 6.63 * 3* 10^-34* 10^8/1.6 *10^-19 * 78* 10^-12 = 0.15937 * 10^5 = 15.93 * 10^* V = 1593 KV.

						
5 years ago
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