The orbital angular momentum of a p-electron is given as : a) b) c) d) .

Question

Arun · Answer

Orbital angular momentum is given by root(l(l+1))*h/2pi where l is the azimuthal quantum no. and h is plank's constant

For p orbit , l=1

Orbital angular momentum = root(2)*h/2pi

Hence option A is correct.

Hope it helps

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The orbital angular momentum of a p-electron is given as : a) b) c) d) .

The orbital angular momentum of a p-electron is given as :
a) $\frac{h}{\sqrt2 \pi}$
b) $\sqrt 3 \frac{h}{2 \pi}$
c) $\sqrt\frac{3}{2} \frac{h}{\pi}$
d) . $\sqrt 6\frac{h}{2\pi}$

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The orbital angular momentum of a p-electron is given as : a) b) c) d) .

The orbital angular momentum of a p-electron is given as :a) b) c) d) .

1 Answers

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The orbital angular momentum of a p-electron is given as :
a) $\frac{h}{\sqrt2 \pi}$
b) $\sqrt 3 \frac{h}{2 \pi}$
c) $\sqrt\frac{3}{2} \frac{h}{\pi}$
d) . $\sqrt 6\frac{h}{2\pi}$