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The no. of alpha particles scattered at 60 0 is 100 per minute in an alpha scattering experiment on gold foil. The no. of aplha particles scattered per minute at 90 0 will be 25 50 16 32

The no. of alpha particles scattered at 600 is 100 per minute in an alpha scattering experiment on gold foil. The no. of aplha particles scattered per minute at 900 will be
  1. 25
  2. 50
  3. 16
  4. 32
     

Grade:12th pass

2 Answers

Arun
25757 Points
2 years ago
it can be shown that number of particlesNscatteredpervunitareaatthetaangle is directly propotional to 1/ sin^4 ( theta/2)
 
Hence N2/100 = ¼
 
so N2 = 25
Vikas TU
14149 Points
2 years ago
Those that passes straight through did so because they didn't encounter any nuclei. The observation that most alpha particles passed straight through the gold foil led Rutherford to conclude that the the positive charge in an atom in concentrated in a very small area, the nucleus. Atoms are mostly empty space

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