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the motion of the particle in a certain transverse wave is given by the expression y=0.2 sin{pi *[x-4t]} metres . the maximum displacement iof the particles is what

sudarsan R , 8 Years ago
Grade 9
anser 2 Answers
Arun
Dear student
 
y = 0.2 sin(pi(x –4t))
 
hence for maximum amplitude
 
function of sin can be 1.
 
thus maximum amplitude
 = 0.2
 
 
Regards
Arun (skIITians forum expert)
Last Activity: 8 Years ago
Saket singh
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