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The minimum number of NAND gates required to implement A+AB'+AB'C ? Plz explain aslo...

The minimum number of NAND gates required to implement A+AB'+AB'C ?
Plz explain aslo...

Grade:12th pass

2 Answers

Saurabh Koranglekar
askIITians Faculty 10341 Points
one year ago
Dear student

Minimal expression is A
No. Of nand gates required is 0

Regards
Vikas TU
14149 Points
one year ago
Dear student 
Above ans is incorrect 

There are two addition Terms and Three inputs

Inputs are a,b,c

for b to b’ conversion one NAND gate is required

For adding two numbers 3 NAND Gates are required

Therefore split the term as Y = a + ab’ + ab’c as

Z = b’ —- One NAND Gate

Z1 = ab’ is an and operation . this requires 3 NAND gates of 2 inputs

Z2 = ab’ + ab’c = Z1(1+c) = Z1 since 1 + c in digital is 1

theretofore Y becomes a + Z1 Totally 4 NAND gates of two input is the Minimal requirement

There are other different methods too for implementation of this function

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