The K base β X-ray of argon has a wavelength of 0.36 nm. The minimum energy needed to ionize an argon atom is 16 eV. Find the energy needed to knock out an electron from the K shell of an argon atom.
Amit Saxena , 11 Years ago
Grade upto college level
1 Answers
Navjyot Kalra
λ = 0.36 nm
E = 1242/0.36 = 2450 eV (E base M – E base K)
Energy needed to ionize an organ atom = 16 eV
Energy needed to knock out an electron from K-shell
= (3450 + 16) eV = 3466 eV = 3.466 KeV.
Last Activity: 11 Years ago
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