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Grade: 9
        
the ionization energy of H atom is 13.6 eV . what will be the  ionization energy of He ^+ and li^2+
9 months ago

Answers : (2)

Arun
14020 Points
							
Dear Aastha
 
Please ask one question in one thread
 
For He+

I.E. = 13.6Z2/n

=  13.6 x Z2 \1[Z =2 for He+]

= 13.6 x 4 = 54.4 eV
 
Regards
Arun (askIITians forum expert)
9 months ago
Arun
14020 Points
							
Dear Aastha
 

for Li2+ = 13.6 x 32/12

= 13.6 x 9 = 122.4 eV
 
Regards
Arun (askIITians forum expert)
 
If you find it useful, please approve it
9 months ago
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