Vikas TU
Last Activity: 7 Years ago
Dear Student,initial velocity=u=10m/sAcceleration = -Retardation= -2 m/s2Velocity after 4 seconds sice we have to find the distance travelled in 5th second= V5=u+at=>V5= 10-2x4 =8m/sDistance moved by the particle in the fifth second = Displacement of the particle in the fifth second (since they are moving in straight line)=>Displacement=ut+at2/2 =2x1-2x1/2 =1mDistance moved=1m.Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)