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The heat generated in a circuit is given by H = I2Rt joule where I is current, R is resistance and t is time. If the percentage errors in measuring I, R and t are 1%, 2% and 1% respectively, the maximum error in measuring heat will be

Navneet kumar , 11 Years ago
Grade Upto college level
anser 4 Answers
Saurabh Singh

Last Activity: 11 Years ago

( error in H) /H= 2*(error in I)/I +( error in R)/R +( error in t)/t


%error in H = 2*1+2+1
=5%

Thanks & Regards

Saurabh Singh,

askIITians Faculty

B.Tech.

IIT Kanpur

Kamlesh Kumar

Last Activity: 11 Years ago

MAXIMUM ERROR IN MEASURING HEAT


?H/H X 100 = 2 X ?I / I X 100 + ? R / R X 100 + ? T / T X 100

= 2 X 1 + 2 + 1 = 5

THANKS &REGARDS
kamlesh kumar
askiitians faculty

Rohit

Last Activity: 6 Years ago

Maximum error = error in Current+error in time +error in resistence
We know that Heat H=I^2RT
Then total error in heat =2×2+1+2=6% answer

Anushka

Last Activity: 5 Years ago

As we know heat=I^2RT
Therefore, the total error in heat% is=(2^2+1+1)
Ans=(4+1+1)=6%.
[NOTE:maximum error =error in current + error in resistance + error in time ]

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