Question icon
Grade 11Modern Physics

The greatest acceleration or deceleration that a train may have a. The minimum time in which the train may reach from one station to the other separated by a distance d is

Profile image of Sumit Soyam
7 Years agoGrade 11
Answers icon

2 Answers

Profile image of Arun
7 Years ago
 
The total distnace train has to cover is d.
The first half it will accelerate and the second half it’ll deaccelerate, and it’ll take half-half time for both acceleration and deacceleration.
 
Hence,
 
d/2 = a/2(t/2)2               (u = 0 ,because the train was at rest initially)
4d/a = t2
t = (4da)½.
Profile image of Khimraj
7 Years ago
Accn and declrcn each have taken time = t/2 S= 1/2(at/2)*t= at^2/4 t= 2√d/a .....................................