Modern Physics> The greatest acceleration or deceleration...

The greatest acceleration or deceleration that a train may have a. The minimum time in which the train may reach from one station to the other separated by a distance d is

Sumit Soyam , 5 Years ago

Grade 11

2 Answers

Arun

Last Activity: 5 Years ago

The total distnace train has to cover is d.

The first half it will accelerate and the second half it’ll deaccelerate, and it’ll take half-half time for both acceleration and deacceleration.

Hence,

d/2 = a/2(t/2)²(u = 0 ,because the train was at rest initially)

4d/a = t²

t = (4da)^½.

Khimraj

Last Activity: 5 Years ago

Accn and declrcn each have taken time = t/2 S= 1/2(at/2)*t= at^2/4 t= 2√d/a .....................................

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Modern Physics> The greatest acceleration or deceleration...

The greatest acceleration or deceleration that a train may have a. The minimum time in which the train may reach from one station to the other separated by a distance d is

Sumit Soyam , 5 Years ago

Arun

Khimraj

LIVE ONLINE CLASSES

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