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Grade: 11
        
The greatest acceleration or deceleration that a train may have a. The minimum time in  which the train may reach from one station to the other  separated by a distance  d is
3 months ago

Answers : (2)

Arun
22533 Points
							
 
The total distnace train has to cover is d.
The first half it will accelerate and the second half it’ll deaccelerate, and it’ll take half-half time for both acceleration and deacceleration.
 
Hence,
 
d/2 = a/2(t/2)2               (u = 0 ,because the train was at rest initially)
4d/a = t2
t = (4da)½.
3 months ago
Khimraj
3008 Points
							
Accn and declrcn each have taken time = t/2 S= 1/2(at/2)*t= at^2/4 t= 2√d/a .....................................
3 months ago
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