The distance travelled by an object along the axes are given as x= 2t2, y=t2-4t, z=3t-5 . What is the initial velocity of the particle
Ashok Kumar , 7 Years ago
Grade 11
1 Answers
Arun
Last Activity: 7 Years ago
Dear Student,
As given in the qstn., x=2t2 (dx/dt)t=0=(Vx)0= initial velocity along x-axis= 4t = 4x0 = 0 y=t2-4t (dy/dt)t=0=(Vy)0= initial velocity along y axis = 2t –4 = – 4 z=3t-5 (dz/dt)t=0=(Vz)0= initial velocity along z axis = 3