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The distance travelled by an object along the axes are given as x= 2t2, y=t2-4t, z=3t-5 . What is the initial velocity of the particle
Dear Student,As given in the qstn.,x=2t2(dx/dt)t=0=(Vx)0= initial velocity along x-axis= 4t = 4x0 = 0y=t2-4t(dy/dt)t=0=(Vy)0= initial velocity along y axis = 2t –4 = – 4z=3t-5(dz/dt)t=0=(Vz)0= initial velocity along z axis = 3Initial resultant velocity= 0i – 4j+3k= – 4j + 3k
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