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question mark

The distance traveled by an object along the axes a
re given by x=2t², y = t² – 4, z = 3 t – 5. What
is the initial velocity of the particle?

Monal Kala , 8 Years ago
Grade 11
anser 1 Answers
Vikas TU
Dear Student,
AAs given in the qstn.,
x=2t2
(dx/dt)t=0=Vx0= initial velocity along x-axis= 4t = 4x0 = 0
y=t2-4
(dy/dt)t=0=Vy0= initial velocity along y axis = 2t = 0
z=3t-5
(dz/dt)t=0=Vz0= initial velocity along z axis = 3
Initial resultant velocity= 0i+0j+3k
=3k (cap).
Last Activity: 8 Years ago
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