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The distance traveled by an object along the axes a re given by x=2t², y = t² – 4, z = 3 t – 5. What is the initial velocity of the particle?

The distance traveled by an object along the axes a
re given by x=2t², y = t² – 4, z = 3 t – 5. What
is the initial velocity of the particle?

Grade:11

1 Answers

Vikas TU
14149 Points
3 years ago
Dear Student,
AAs given in the qstn.,
x=2t2
(dx/dt)t=0=Vx0= initial velocity along x-axis= 4t = 4x0 = 0
y=t2-4
(dy/dt)t=0=Vy0= initial velocity along y axis = 2t = 0
z=3t-5
(dz/dt)t=0=Vz0= initial velocity along z axis = 3
Initial resultant velocity= 0i+0j+3k
=3k (cap).

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