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The distance between the cathode (filament) and the target in an X-ray tube is 1.5 m. If the cutoff wavelength is 30 pm, find the electric field between the cathode wavelength decrease?

The distance between the cathode (filament) and the target in an X-ray tube is 1.5 m. If the cutoff wavelength is 30 pm, find the electric field between the cathode wavelength decrease?

Grade:11

1 Answers

Aditi Chauhan
askIITians Faculty 396 Points
7 years ago
d = 1.5 m, λ = 30 pm = 30 * 10^-3 nm E = hc/λ = 1242/30* 10^3 = 41.4 * 10^eV Electric field = V/d = 41.4* 10^3/1.5 = 27.6 * 10^3 V/m = 27.6 KV/m.

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