The current in the forward bias is known to be more (~mA) than the current in
the reverse bias (~đA). What is the reason, then, to operate the photodiode in reverse
bias?
The current in the forward bias is known to be more (~mA) than the current in
the reverse bias (~đA). What is the reason, then, to operate the photodiode in reverse
bias?
the reverse bias (~đA). What is the reason, then, to operate the photodiode in reverse
bias?










