the body starting from rest and travelling with uniform acceleretion covers 15mduring the third second during 5th second how much distance will it cover

Dear Student,
Given that initial velocity is:
u=0, uniform acceleration=a
S=ut+at²/2
=>15=2a+a/2 (Since t=1, for the n^th second and u should be the velocity after 2 seconds since we are equating it with the distance travelled in the third second)
=>a=6m/s²

Velocity after 4s = u+at
=0+4a=4a
Distance covered in 5^th second=S= ut+at²/2
=>S=4a+a/2
=>S=27m