the body starting from rest and travelling with uniform acceleretion covers 15m during the third second during 5^th second how much distance will it cover

Dear Student,
Given that initial velocity is:
u=0, uniform acceleration=a
S=ut+at²/2
=>15=2a+a/2 (Since t=1, for the n^th second and u should be the velocity after 2 seconds since we are equating it with the distance travelled in the third second)
=>a=6m/s²

Velocity after 4s = u+at
=0+4a=4a
Distance covered in 5^th second=S= ut+at²/2
=>S=4a+a/2
=>S=27m