The 1st resistance is 4 ohms, the second is 6 ohms and the third is 3 ohms.Find the current thru the battery.

If u check in the circuit since we are not given any cut off voltage for the diodes so we consider that the diode behave like a wire and circuit gets shorted due to which current flows through only 6 and 3 ohms resistance not from 4ohms. 6 and 3 ohm are in parallel so net resistance become 2 ohms [net Resistance = (R¹ X R²) ÷ (R¹ + R²)] .Therefore current flowing through battery is 15 Amperes.