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stone is thrown upwards with velocity v. At half the height, its velocity is
(a) zero
(b) v/4
(c) v/2
(d) v/1.414

venkata ramana , 8 Years ago
Grade 11
anser 1 Answers
Vikas TU

Last Activity: 8 Years ago

Total height it traversed =>
0^2 = v^2 – 2gH
H = v^2/2g...............................(1)
At half the height.
v’^2 = v^2 – 2g(H/2)
v’^2 = v^2 – v^2/2 = > v^/2 {from eqn. (1)}
v’ = v/root(2) m/s
d option.

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