Sir , jee mains 2 nd shift april 12 question from

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Sir , jee mains 2 nd shift april 12 question from atoms and nuclei , what is its answer? Can u plz help me out?

sree lakshmi · Accepted Answer

Electron in hydrogen atom first jumps from third excited state to second excited state and then from second excited to the first excited state. The ratio of the wavelengths &lambda;1:&lambda;2 emitted in the two cases is ans; 1st the electron jumps from 3rd excited state to the 2nd ie from n=4 to n=3 then 1/&lambda;1 =R(1/n12 -1/n22 )= R ( 1/9 &ndash; 1/16) =R (7/144) similarly 1/&lambda;2 = R ( &frac14; &ndash; 1/9 )=R(5/36) &there4; &lambda;1/&lambda;2 = 1/R(144/7) * R (5/36) =4*5/7 =20/7 so the ans is 20/7

Modern Physics> Sir , jee mains 2 nd shift april 12 quest...

Sir , jee mains 2 nd shift april 12 question from atoms and nuclei , what is its answer? Can u plz help me out?

abhishek premerajan , 6 Years ago

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Modern Physics> Sir , jee mains 2 nd shift april 12 quest...

Sir , jee mains 2 nd shift april 12 question from atoms and nuclei , what is its answer? Can u plz help me out?

abhishek premerajan , 6 Years ago

sree lakshmi

Provide a better Answer & Earn Cool Goodies

LIVE ONLINE CLASSES

Ask a Doubt

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