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Resistance of a metal wire of lenght 2m is 26 ohm at 20°c if the diameter of the wire is 0.3 mm ,what will be the resistivity of metal at that temperature?

Shreya D Nanda
74 Points
4 years ago
HI,
We can use the formula :$R= \rho L/A$ , where, R is resistance of the wire, L its length, A its cross-sectional area and $\rho$ [rho] is the resistivity of the wire.
From the data given, $R=26 \Omega$$L=2m$  and    $A=\pi[0.3*10^{-3}]^{2} m^{}2$    i.e, $A= 9*10^{-8}\pi m^{2}$

$\rho =RA/L$  $\Rightarrow \rho = 26 * 9*10^{-8}\pi /2$
$\therefore \rho = 367.38 * 10^{-8} \Omega m$
or $\rho = 3.674 * 10^{-6} \Omega m$

Hope it helps, thanks..