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radioactive material A with initial number and decays to material B and B find the decays to material C with decay constant lambda1 and lambda2. the number of atom of B is maximum at time t = t not , then the maximum number of atoms of material B is

radioactive material A with initial number and decays to material B and B find the decays to material C with decay constant lambda1 and lambda2. the number of atom of B is maximum at time t = t not ,  then the maximum number of atoms of material B is

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Grade:12

1 Answers

RHYTHM KAUSHAL
askIITians Faculty 56 Points
one year ago
dear student,
follow the attached answer611-1673_WhatsApp Image 2020-07-15 at 21.00.01.jpeg

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