Q) The maximum power which can be transferred to the load resistor with a signal of 2V by a triode, where

r_p= 2000 ohm u = 20 is----

1) 2W 2) 0.2W 3) 20W 4) 0.02W

To determine the maximum power that can be transferred to the load resistor in this scenario, we can use the concept of maximum power transfer theorem, which states that maximum power is delivered to the load when the load resistance equals the output resistance of the source. In this case, we have a triode with a plate resistance (r_p) of 2000 ohms and a signal voltage (u) of 2V.

Understanding the Parameters

Let's break down the parameters given:

• Signal Voltage (u): 2V
• Plate Resistance (r_p): 2000 ohms
• Transconductance (g_m): This is often denoted as 'u' in some contexts, and here it is given as 20.

Calculating Maximum Power Transfer

To find the maximum power transferred to the load, we first need to calculate the current flowing through the load resistor when it is matched to the plate resistance. The formula for current (I) can be derived from Ohm's law:

I = V / R

In our case, the voltage (V) is the signal voltage (2V), and the resistance (R) is the plate resistance (2000 ohms). Thus, we can calculate the current:

I = 2V / 2000 ohms = 0.001 A (or 1 mA)

Calculating Power

Now that we have the current, we can calculate the power (P) using the formula:

P = I² * R

Substituting the values we have:

P = (0.001 A)² * 2000 ohms

P = 0.000001 A² * 2000 ohms = 0.002 W

To express this in a more standard form, we can convert it to milliwatts:

P = 0.002 W = 2 mW

Final Consideration

However, we need to ensure that we are looking for the maximum power that can be transferred to the load resistor. The options provided are:

• 1) 2W
• 2) 0.2W
• 3) 20W
• 4) 0.02W

Given our calculation of 0.002 W (or 2 mW), none of the options directly match this value. However, if we consider the closest option, it would be 0.02W (which is 20 mW), but it is still not an exact match. This discrepancy may arise from rounding or assumptions in the problem setup.

In conclusion, based on the calculations, the maximum power that can be transferred to the load resistor is approximately 0.002 W, which is not listed among the options. However, if we had to choose the closest option, it would be 0.02W. Always ensure to double-check the parameters and calculations in such problems to avoid any confusion.