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Please sir answer question 12...I have posted it twice but u are not giving answer. ..Please sir anwer it with details

Please sir answer question 12...I have posted it twice but u are not giving answer. ..Please sir anwer it with details

Question Image
Grade:12th pass

1 Answers

Arun
25763 Points
3 years ago
Dear student
 
We have the relation  λ = h/mv,
where m = 9.1 x 10-31 kg, is the mass of the electron,
h = 6.6 x 10-34 J.s, is the Planck's constant
v the velocity of the electron.
Since kinetic energy  E = ½mv2,  we can write mv = (2mE)   ⇒  E = h2/(2mλ2)
We have for hydrogen atom, IEI = 13.6/n2, where n is the principal quantum number.
13.6/n2  = h2/(2mλ2)
 = (6.6 x 10
-34 J.s)2/(2 x 9.1 x 10-31 kg x 10-9x2 m)
This gives n = 2.99 ? 3

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