Last Activity: 7 Years ago
26Fe – 1s2, 2s2 2p6, 3s2 2p6, 3d6, 4s2
+ m = 0 P = 0, m = 0 i.e. s-subshell
= 1, m = –1 i.e. one orbital of p
= 2, m = 2 i.e. one of d-orbitals
hence there are 13 and 14 electron as in d-orbital it may be one or two electron having m = –2.
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Get your questions answered by the expert for free
Last Activity: 2 Years ago